mufs: implement block allocation

tags/0.1.0
S.J.R. van Schaik 7 years ago
parent 7172423f05
commit f4b08bb89f
  1. 1
      Makefile
  2. 68
      source/fs/mufs/block.c
  3. 4
      source/fs/mufs/block.h

@ -23,6 +23,7 @@ obj-y += source/main.o
obj-y += source/core/flash.o
obj-y += source/fs/mufs/block.o
obj-y += source/fs/mufs/super.o
obj-y += source/ftl/dev.o

@ -0,0 +1,68 @@
#include <bitops.h>
#include <flash.h>
#include <macros.h>
#include <fs/mufs.h>
#include "block.h"
static int mufs_mark_block(struct mufs *fs, uint32_t block, int status)
{
char data[1 << fs->dev->log2_block_size];
uint8_t log2_bits_per_block = fs->dev->log2_block_size + ilog2(8);
size_t index;
index = block & ((UINT32_C(1) << log2_bits_per_block) - 1);
block >>= log2_bits_per_block;
if (flash_read(fs->dev, (1 + block) << fs->dev->log2_block_size, data,
sizeof data) == 0)
return -1;
if (status) {
set_bit(data, index);
} else {
clear_bit(data, index);
}
if (flash_write(fs->dev, (1 + block) << fs->dev->log2_block_size, data,
sizeof data) == 0)
return -1;
return 0;
}
int mufs_alloc_block(struct mufs *fs, uint32_t *found)
{
char data[1 << fs->dev->log2_block_size];
uint32_t nblocks = fs->nblocks;
uint32_t nbits;
uint32_t block = 0;
size_t index;
uint8_t log2_bits_per_block = fs->dev->log2_block_size + ilog2(8);
while (nblocks) {
if (flash_read(fs->dev, (1 + block) << fs->dev->log2_block_size, data,
sizeof data) == 0)
return -1;
nbits = min(nblocks, UINT32_C(1) << log2_bits_per_block);
if ((index = next_clear_bit(data, nbits)) == SIZE_MAX) {
++block;
nblocks -= nbits;
continue;
}
*found = (block << log2_bits_per_block) + index;
return mufs_mark_block(fs, *found, 1);
}
return -1;
}
int mufs_free_block(struct mufs *fs, uint32_t block)
{
return mufs_mark_block(fs, block, 0);
}

@ -0,0 +1,4 @@
#pragma once
int mufs_alloc_block(struct mufs *fs, uint32_t *block);
int mufs_free_block(struct mufs *fs, uint32_t block);
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