dtoc: Adjust Node to record its parent

We need to be able to search back up the tree for #address-cells and
 #size-cells. Record the parent of each node to make this easier.

Signed-off-by: Simon Glass <sjg@chromium.org>
Reviewed-by: Philipp Tomsich <philipp.tomsich@theobroma-systems.com>
Tested-by: Philipp Tomsich <philipp.tomsich@theobroma-systems.com>
Tested-by: Kever Yang <kever.yang@rock-chips.com>
master
Simon Glass 7 years ago
parent 93c94b889b
commit 979ab02473
  1. 12
      tools/dtoc/fdt.py

@ -174,8 +174,9 @@ class Node:
props: A dict of properties for this node, each a Prop object.
Keyed by property name
"""
def __init__(self, fdt, offset, name, path):
def __init__(self, fdt, parent, offset, name, path):
self._fdt = fdt
self.parent = parent
self._offset = offset
self.name = name
self.path = path
@ -217,7 +218,7 @@ class Node:
sep = '' if self.path[-1] == '/' else '/'
name = self._fdt._fdt_obj.get_name(offset)
path = self.path + sep + name
node = Node(self._fdt, offset, name, path)
node = Node(self._fdt, self, offset, name, path)
self.subnodes.append(node)
node.Scan()
@ -279,7 +280,7 @@ class Fdt:
TODO(sjg@chromium.org): Implement the 'root' parameter
"""
self._root = self.Node(self, 0, '/', '/')
self._root = self.Node(self, None, 0, '/', '/')
self._root.Scan()
def GetRoot(self):
@ -386,7 +387,7 @@ class Fdt:
return libfdt.fdt_off_dt_struct(self._fdt) + offset
@classmethod
def Node(self, fdt, offset, name, path):
def Node(self, fdt, parent, offset, name, path):
"""Create a new node
This is used by Fdt.Scan() to create a new node using the correct
@ -394,11 +395,12 @@ class Fdt:
Args:
fdt: Fdt object
parent: Parent node, or None if this is the root node
offset: Offset of node
name: Node name
path: Full path to node
"""
node = Node(fdt, offset, name, path)
node = Node(fdt, parent, offset, name, path)
return node
def FdtScan(fname):

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