cmd_test: implement ! on sub-expressions

Currently, ! can only be parsed as the first operator in an expression.
This prevents the following from working:

$ if test ! ! 1 -eq 1; then echo yes; else echo no; fi
yes
$ if test ! 1 -eq 2 -a ! 3 -eq 4; then echo yes; else echo no; fi
yes

Fix this by parsing ! like any other operator, and and handling it
similarly to -a and -o.

Signed-off-by: Stephen Warren <swarren@nvidia.com>
master
Stephen Warren 11 years ago committed by Tom Rini
parent 4c80f29edd
commit d9b651ce31
  1. 43
      common/cmd_test.c

@ -18,6 +18,7 @@
#include <command.h>
#define OP_INVALID 0
#define OP_NOT 1
#define OP_OR 2
#define OP_AND 3
#define OP_STR_EMPTY 4
@ -49,6 +50,7 @@ const struct {
{1, "-le", OP_INT_LE, 3},
{1, "-gt", OP_INT_GT, 3},
{1, "-ge", OP_INT_GE, 3},
{0, "!", OP_NOT, 1},
{0, "-o", OP_OR, 1},
{0, "-a", OP_AND, 1},
{0, "-z", OP_STR_EMPTY, 2},
@ -58,7 +60,7 @@ const struct {
static int do_test(cmd_tbl_t *cmdtp, int flag, int argc, char * const argv[])
{
char * const *ap;
int i, op, left, adv, expr, last_expr, neg, last_cmp;
int i, op, left, adv, expr, last_expr, last_unop, last_binop;
/* args? */
if (argc < 3)
@ -73,17 +75,11 @@ static int do_test(cmd_tbl_t *cmdtp, int flag, int argc, char * const argv[])
}
#endif
last_expr = 0;
left = argc - 1; ap = argv + 1;
if (left > 0 && strcmp(ap[0], "!") == 0) {
neg = 1;
ap++;
left--;
} else
neg = 0;
left = argc - 1;
ap = argv + 1;
expr = -1;
last_cmp = OP_INVALID;
last_unop = OP_INVALID;
last_binop = OP_INVALID;
last_expr = -1;
while (left > 0) {
for (i = 0; i < ARRAY_SIZE(op_adv); i++) {
@ -152,27 +148,36 @@ static int do_test(cmd_tbl_t *cmdtp, int flag, int argc, char * const argv[])
switch (op) {
case OP_OR:
last_expr = expr;
last_cmp = OP_OR;
last_binop = OP_OR;
break;
case OP_AND:
last_expr = expr;
last_cmp = OP_AND;
last_binop = OP_AND;
break;
case OP_NOT:
if (last_unop == OP_NOT)
last_unop = OP_INVALID;
else
last_unop = OP_NOT;
break;
default:
if (last_cmp == OP_OR)
if (last_unop == OP_NOT) {
expr = !expr;
last_unop = OP_INVALID;
}
if (last_binop == OP_OR)
expr = last_expr || expr;
else if (last_cmp == OP_AND)
else if (last_binop == OP_AND)
expr = last_expr && expr;
last_cmp = OP_INVALID;
last_binop = OP_INVALID;
break;
}
ap += adv; left -= adv;
}
if (neg)
expr = !expr;
expr = !expr;
debug (": returns %d\n", expr);

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